-
Hi @StevenArzt , @t1mlange
I am working on analyzing Android Apps, I included API used to retrieve contact, sms and media in the source and sink file.
Flowdroid does identify these sources and si…
-
### Current Behavior
Issue35Test makes everything slow in Android Instrumented Test
-
There is no reason to refactor functionality already provided by a 3rd party crate. The [siphasher]( https://crates.io/crates/siphasher) crate likely provides the requisite functionality and appears t…
-
# 递归的理解
递归最常见的应用是在数学和计算机科学中,在计算机科学中,程序调用自身的编程技巧就是递归。
![p772261130 副本](https://user-images.githubusercontent.com/7975643/71308286-7f8c7700-2435-11ea-9a4e-2cdb04e028bd.jpg)
当递归没有终止条件时,就是无限递归,…
-
Before :
```java
Map a = new Hashmap();
a.add("hello","world");
Map b = new HashMap();
for (Map.Entry s : a.entrySet()){
b.put(s.getKey(),s.getValue());
}
// Lists
List l1 = ne…
-
```
If we have a subclass of HashMap without a default constructor, Gson uses
LinkedHashMap as the object type. This isn't correct since we should have
instead tried to use UnsafeAllocator.
```
Ori…
-
```
If we have a subclass of HashMap without a default constructor, Gson uses
LinkedHashMap as the object type. This isn't correct since we should have
instead tried to use UnsafeAllocator.
```
Ori…
-
```
If we have a subclass of HashMap without a default constructor, Gson uses
LinkedHashMap as the object type. This isn't correct since we should have
instead tried to use UnsafeAllocator.
```
Ori…
-
```
If we have a subclass of HashMap without a default constructor, Gson uses
LinkedHashMap as the object type. This isn't correct since we should have
instead tried to use UnsafeAllocator.
```
Ori…
-
```
If we have a subclass of HashMap without a default constructor, Gson uses
LinkedHashMap as the object type. This isn't correct since we should have
instead tried to use UnsafeAllocator.
```
Ori…