Popup position shifts after enabling .tapOutsideToDismiss(true) and dismissing by tapping outside

[El549]

Description:

I'm using the PopupView framework and have encountered an issue when I enable .tapOutsideToDismiss(true) to allow dismissing the popup by tapping outside. The specific problem is:

• After triggering the popup for the first time and dismissing it by tapping outside, it seems that the gesture detection remains active.
• When I trigger the popup again, the initial position of the popup shifts and does not appear at the expected location.

Steps to Reproduce:

1. Configure PopupView with .tapOutsideToDismiss(true) enabled.
2. Trigger the popup to display.
3. Dismiss the popup by tapping outside.
4. Trigger the popup again.

Expected Behavior:

• The popup should appear at the same initial position every time it is displayed.

Actual Behavior:

• On the second and subsequent displays, the popup's position is shifted and not at the original expected location.

Possible Cause:

• After dismissing the popup, the gesture detection is not properly removed, causing incorrect position calculations the next time the popup is displayed.

Additional Information:

• I can provide relevant code snippets or a demo video if needed.

I hope the developers can look into this issue. Thank you very much!

[FulcrumOne]

Hey @El549,

The problem should be fixed in the newest framework version.

Have a nice day, Tomasz