How to recreate a counter in the same position (i.e. how to destroy a counter as well as its position)

[yusanshi]

Is your feature request related to a problem? Please describe. Sometimes I want to create several counters in the same specified position, but it will raise Counter position {} is already occupied. error. So I would like to know how can I release a counter and then create another in the same position.

An example:

import enlighten
import numpy as np

batches = np.random.uniform(size=(20, 20))

def train(batch):
    pass

manager = enlighten.get_manager()

for epoch in range(10):
    pbar = manager.counter(total=len(batches), position=0)
    for batch in pbar(batches):
        train(batch)

Describe the solution you'd like A function to destroy a counter as well as its position.

Describe alternatives you've considered A function to reset a counter (reset its escape time and current count value).

[avylove]

I have been thinking about adding a replace() method to make transitions like this easier. However, I think for your use case, you can add leave=False and then close the counter when you're finished. You may also find using position 1 will give you better results than position 0.

import time

import enlighten
import numpy as np

batches = np.random.uniform(size=(20, 20))

def train(batch):
    time.sleep(0.1)

manager = enlighten.get_manager()

for epoch in range(10):
    pbar = manager.counter(desc=str(epoch), total=len(batches), position=1, leave=False)
    for batch in pbar(batches):
        train(batch)
    pbar.close()

[avylove]

Additionally, in this use case, you'll find you don't need to specify the position at all, though perhaps in your project you do. You can also close implicitly using a context manager:

for epoch in range(10):
    with manager.counter(desc=str(epoch), total=len(batches), leave=False) as pbar:
        for batch in pbar(batches):
            train(batch)

[yusanshi]

Thanks for your timely reply. leave=False does the trick.