Closed GoogleCodeExporter closed 9 years ago
Upon further thinking, it seems impossible to support more than one meta facets
simultaneously. Consider two
meta facets A and B both of which have selections. In order for A to
instantiate its RowFilter, it must first compute
its choice/count pairs. In order to do so, A needs a FilteredRows that
incorporates the RowFilter by B. And vice
versa: for B to instantiate its RowFilter it needs the RowFilter by A.
Not all is lost, though. Instead of meta facets, what we can easily support is
a command that creates a new
column and fill it in with facet choice counts. Then a numeric range facet can
be used on that new column. The
drawback is that those counts don't change dynamically.
Original comment by dfhu...@gmail.com
on 23 May 2010 at 5:56
I tried to do this manually - creating two facets for two different columns (I
was
using the movie sample data from the test data folder in the SVN trunk). It
seems to
work, so I'm not sure why we couldn't do it in code?
I created one for performances-actor and another for performances-character. I
sorted performances-actor by count and selected all actors with counts above 5
(Mike
Myers, Eddie Murphy & Cameron Diaz). I then sorted characters and selected all
characters with counts above 3 (Princess Fiona, Shrek, Donkey). As each
character
was selected the actor count was filtered and updated.
Original comment by iainsproat
on 23 May 2010 at 7:11
@iainsproat: you were probably lucky to get a case that works. Actually you
don't need 2 meta facets to have a
problem here. Just 1 meta facet and some regular facets are enough to cause
problems.
Consider a data set with 3 rows and 2 columns
A C
A D
B D
Consider 3 facets
Text facet P on first column
A (2)
B (1)
Text facet Q on second column
C (1)
D (2)
Meta facet M on first column (that is, M is meta with respect to P)
count of 2 (1)
count of 1 (1)
Now, in M, select count of 2:
M
count of 2 (1) -selected
count of 1 (1)
P
A (2)
Q
C (1)
D (1)
If in Q you select C, what do you expect to happen? Ignore M for the moment and
consider P. Selecting C in Q
would change P to
P
A (1)
This is because only exactly 1 row has C. But since M selects any row that
corresponds to a choice in P with
count 2, now M must select no row at all.
One solution is as I mentioned before to create a column with the facet counts.
Another solution is to make meta facets not affected by other facets
(nullifying the problem in the example
above). That is, making selections in other facets shouldn't change a meta
facet's choices. M only work with the
choice counts in P when there is no facet selection whatsoever.
The pros here include less data getting stored, fewer clicks to get what you
want, and thus more interactivity.
The cons include potential confusion as to how facets in general affect one
another. I think with the right design
the confusion can be mitigated. It's probably one of those cases where it would
work as you expect if you don't
think too much about it.
I'm leaning toward the second approach. It shouldn't be too hard to implement.
Original comment by dfhu...@gmail.com
on 23 May 2010 at 6:05
Fixed by r848. For any text facet, scroll down to the bottom of its choice
list. You should see "facet by choice
counts". Click on that and you'd get a numeric range facet.
Original comment by dfhu...@gmail.com
on 24 May 2010 at 7:10
Original comment by tfmorris
on 18 Sep 2012 at 2:56
Original issue reported on code.google.com by
dfhu...@gmail.com
on 22 May 2010 at 11:40