mustansarfiaz
commented
5 years ago Never mind, solved it for windows. line 20-21
key=lambda x:int(str(x).split('\\')[-1:][0].split('.')[0]))
video_name = str(video_dir).split('\\')[-1]
Closed mustansarfiaz closed 5 years ago
mustansarfiaz
commented
5 years ago Never mind, solved it for windows. line 20-21
key=lambda x:int(str(x).split('\\')[-1:][0].split('.')[0]))
video_name = str(video_dir).split('\\')[-1]
I am facing error at line 67 in create_dataset.py Please help me to solve the issue. ValueError: invalid literal for int() with base 10: 'a\ILSVRC2015_train_00000000\000000'