Closed chrislim5 closed 4 years ago
Using a manual legend is the only 'easy' way to do this. But it's not difficult once you know how colourvalues
works
library(mapdeck)
set_token(secret::get_secret("MAPBOX"))
colours <- colourvalues::color_values( df$val, n_summaries = 5 )
df <- capitals
df$val <- rnorm(nrow(df))
df$colour <- colours$colours
l <- legend_element(
variables = rev(colours$summary_values)
, colours = rev(colours$summary_colours)
, colour_type = "fill"
, variable_type = "gradient"
)
mapdeck() %>%
add_scatterplot(
data = df
, fill_colour = "colour"
, tooltip = "val"
, radius = 100000
, legend = mapdeck::mapdeck_legend(l)
)
Great, thanks! That helped a lot. If I want to use a reversed color palette with this method, what is the best way to do this? Previously I had been reversing the palette using palette = colourvalues::get_palette("inferno")[256:1, ]
when adding a layer. This seems to work:
colors <- colourvalues::color_values(data$percentile, palette = "inferno", n_summaries = 5)
data$colour <- colors$colours
leg <-
legend_element(
variables = rev(colors$summary_values),
colours = colors$summary_colours,
colour_type = "stroke",
variable_type = "gradient"
)
mapdeck(style = mapdeck_style("light"), zoom = 11) %>%
add_path(data = data,
stroke_colour = "percentile",
stroke_width = 5,
palette = colourvalues::get_palette("inferno")[256:1,],
legend = mapdeck_legend(leg),
tooltip = "label_text",
layer_id = "path_layer")
Is there a way to reverse the palette when creating the colors in color_values()
?
yeah, supply the reversed palette to the palette
argument
colourvalues::colour_values(
x = 1:20
, palette = colourvalues::get_palette("inferno")[256:1, ]
)
Is it possible to reverse the order of the legend (highest values on top, lowest on bottom) without manually building a new legend? I tried adding legend_format = list(stroke_colour = rev), but that only changes values on the legend and not the colors.