Iterator, Generator, Decorator

XudayberdiyevB commented 1 year ago

get_next_multiple nomli generator yarating, bunda generator funksiya bitta son qabul qiladi. Yaratilgan generator obyekt next() orqali olganda berilgan son keyingi bo'luvchilarini qaytarsin.
```
gen_multiple_of_two = get_next_multiple(2)
next(gen_multiple_of_two) # 2
next(gen_multiple_of_two) # 4
next(gen_multiple_of_two) # 6
next(gen_multiple_of_two) # 8
```

gen_multiple_of_thirteen = get_next_multiple(13)

next(gen_multiple_of_thirteen) # 13 next(gen_multiple_of_thirteen) # 26 next(gen_multiple_of_thirteen) # 39 next(gen_multiple_of_thirteen) # 52

2. `get_next_prime` generator funksiya yarating, bunda 1 dan 1000 gacha sonlar orasida tub sonlarni `next()` orqali olish mumkin bo'lsin.
```python
prime_generator = get_next_prime()
print(next(prime_generator))  # 2
print(next(prime_generator))  # 3
print(next(prime_generator))  # 5

Ikkita sonni qo'shadigan funksiyaga dekorator qo'shing, bunda funksiya qiymati 2 ga ko'payirilgan holda qaytarilsin.
```
add(2, 3)  # 10
add(5, 5)  # 20
```
only_even_parameters nomli dekorator yarating, bunda quyidagi funksiyallarda ishlating va tegishli natija qaytaring.
```
@only_even_parameters
def add(a, b):
return a + b
```

print(add(6, 8)) # 14 print(add(1, 4)) # Please add only even numbers!

```python
@only_even_parameters
def multiply(a, b, c, d):
    return a * b * c * d

print(multiply(6, 4, 2, 2))  # 96
print(multiply(1, 4, 2, 2))  # Please multiple only even numbers!

sum_index nomli funksiya yarating va bu funksiya faqat list qabul qilsin. Funksiya berilgan list indexlari yig'indisini qaytarsin. Funksiyaga beriladigan argumentni tekshirish uchun dekorator yozing.
```
sum_index([2, 4, 5, 6])  # 6
sum_index((2, 4, 5, 6))  # Please send only list.
```