Closed PokerN closed 8 years ago
The location of project mentioned before is /src/std/zsc-seq/
Thanks Nan Nan,
I have not worked in this code for several years, so I need to set some time aside to go over this. It is possible I have made a mistake, so it is important to figure this out.
I'll try to find some time this week to investigate this issue and get back to you.
Regards, Carlos
On Thu, May 19, 2016 at 5:50 AM, Nan Nan notifications@github.com wrote:
Hi, I've downloaded your code, and learned a lot of skills from your work. So thank you for your sharing. However, when I read the collision and stream part, I found there may be something different from the original algorithm. Details : The original order parameter LB equation is : [image: zsc_eq1] https://cloud.githubusercontent.com/assets/8172625/15384925/a0c263fe-1dd0-11e6-8215-9a636eb7a073.png Your implementation:
collsion:
Af1 = 0.5D0_Gamma_muPhi Af0 = -2.D0_Gamma_muPhi Cfp = invEta2phin f(i,j,0,nxt) = f(i,j,0,now) + invTauPhi( Af0 + phin - f(i,j,0,now) ) f(i,j,1,now) = f(i,j,1,now) + invTauPhi_( Af1 + Cfpux - f(i,j,1,now) ) f(i,j,2,now) = f(i,j,2,now) + invTauPhi( Af1 + Cfpuy - f(i,j,2,now) ) f(i,j,3,now) = f(i,j,3,now) + invTauPhi( Af1 - Cfpux - f(i,j,3,now) ) f(i,j,4,now) = f(i,j,4,now) + invTauPhi( Af1 - Cfp_uy - f(i,j,4,now) )
- streaming:
! Identify near neighbors ie = ni(i,j,1) jn = ni(i,j,2) iw = ni(i,j,3) js = ni(i,j,4)! Relax and stream order parameter distribution function f(ie, j,1,nxt) = eta_f(i,j,1,now) + eta2_f(ie,j,1,now) f( i,jn,2,nxt) = eta_f(i,j,2,now) + eta2_f(i,jn,2,now) f(iw, j,3,nxt) = eta_f(i,j,3,now) + eta2_f(iw,j,3,now) f( i,js,4,nxt) = eta_f(i,j,4,now) + eta2_f(i,js,4,now)
It seems that the code actually act in accordance with the other equations as shown below: 1、 collision (Eq1): [image: zsc_eq2s] https://cloud.githubusercontent.com/assets/8172625/15390686/b2e60e40-1def-11e6-955e-7458ed3320f1.png 2、stream (Eq2):
[image: zsc_eq3s] https://cloud.githubusercontent.com/assets/8172625/15390693/be44f508-1def-11e6-83ed-5ccad4a66fe9.png
where eta is : [image: zsc_eq4s] https://cloud.githubusercontent.com/assets/8172625/15390699/c3af4b92-1def-11e6-8d73-f8daa59859bb.png
Unfortunately, I couldn't get the original formula from eq1 and eq2. Maybe I misunderstand your solution. Looking forward to your reply.
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GUE Tech I Diver Slow is smooth, smooth is fast
Let me go over the original formulation and see if this is an actual issue. hat is the term that you are missing when you try to recover the original equation set?
I think I see the problem. This would give additional terms involving the equilibrium distribution function for f(x+dx,t). Before I go ahead and modify the code I'll run the equations once more to make sure this is not something I need to undo later on, but so far I think you are right!
Hi, Carlos
Thank you for your attention! Because of the time difference, I 'm sorry that I can't get your message in time. Recently, I have modified the code based on my comprehension. As long as I changed a little, then it will give me wrong results. So, I am very confused now.
Waiting for your result!
Yours, Nan
I think the key is how to implement the term fi(x+ ci dt, t), as you know, that is unusual with standard LB equation. It doesn't mentioned clearly in 06's paper. What I mean is, the value of fi(x + ci dt, t) is pre-collision or post-collision. If it's post-collision, then what collision form it does.
After further discussion it looks like if we interpret the original equations in any other way other than that implemented the code does not produce physical data, so no changes are actually needed.
Hi, I've downloaded your code, and learned a lot of skills from your work. So thank you for your sharing. However, when I read the collision and stream part, I found there may be something different from the original algorithm. Details : The original order parameter LB equation is :
Your implementation:
It seems that the code actually act in accordance with the other equations as shown below: 1、 collision (Eq1):
2、stream (Eq2):
where eta is :
Unfortunately, I couldn't get the original formula from eq1 and eq2. Maybe I misunderstand your solution. Looking forward to your reply.