ecphp / cas-bundle

CAS Bundle, a standard Symfony bundle for authentication using CAS protocol.
https://ecphp-cas-bundle.readthedocs.io
BSD 3-Clause "New" or "Revised" License
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Use of mutation testing in cas-bundle - Help needed #74

Closed belene closed 1 year ago

belene commented 2 years ago

Hello there!

My name is Ana. I noted that you use the mutation testing tool infection in the project. I am a postdoctoral researcher at the University of Seville (Spain), and my colleagues and I are studying how mutation testing tools are used in practice. With this aim in mind, we have analysed over 3,500 public GitHub repositories using mutation testing tools, including yours! This work has recently been published in a journal paper available at https://link.springer.com/content/pdf/10.1007/s10664-022-10177-8.pdf.

To complete this study, we are asking for your help to understand better how mutation testing is used in practice, please! We would be extremely grateful if you could contribute to this study by answering a brief survey of 21 simple questions (no more than 6 minutes). This is the link to the questionnaire https://forms.gle/FvXNrimWAsJYC1zB9.

Drop me an e-mail if you have any questions or comments (anasan@us.es). Thank you very much in advance!!

drupol commented 1 year ago

Hello,

I received the multiple emails on my personal mailbox and the issues you've opened.

I won't be able to help you, hope you'll find the right person.

belene commented 1 year ago

Hello Pol,

Sorry for the inconvenience.

Regards, Ana

El jue, 1 dic 2022 a las 16:48, Pol Dellaiera @.***>) escribió:

Hello,

I received the multiple emails on my personal mailbox and the issues you've opened.

I won't be able to help you, hope you'll find the right person.

— Reply to this email directly, view it on GitHub https://github.com/ecphp/cas-bundle/issues/74#issuecomment-1333972470, or unsubscribe https://github.com/notifications/unsubscribe-auth/AABIEC4GUDAGH22KVWZF2OLWLDCGVANCNFSM6AAAAAASPM6IXY . You are receiving this because you authored the thread.Message ID: @.***>