json_typegen!("<typename>", <valid source>);
// ...
let foo: <typename> = <parsed JSON with same shape as source>;
Cases where that is currently not the case:
The source JSON is a collection. The typename will be used as the type of the elements of the collection. E.g. json_typegen!("Foobar", ... will require you to parse to Vec<Foobar>.
Code generation tries to be "helpful" and create a more suitable type name, e.g.
json_typegen!("point", r#"{ "x": 1, "y": 2 }"#); will create the type Point
json_typegen!("foo_bar", r#"{ "x": 1, "y": 2 }"#); will create the type FooBar
json_typegen!("Points", r#"[{ "x": 1, "y": 2 }]"#); will create the type Point, so you get a Vec<Point>, but will not define Points
For all cases where the requested type name is legal it should be possible to just reserve the name up front, and then add an alias. Just have to make sure to allow a named root type to use the requested type (e.g. type Point = Point1; struct Point1 { ... } would be a bit silly`).
Code like this should preferably always be legal:
Cases where that is currently not the case:
The source JSON is a collection. The typename will be used as the type of the elements of the collection. E.g.
json_typegen!("Foobar", ...will require you to parse toVec<Foobar>.Code generation tries to be "helpful" and create a more suitable type name, e.g.
json_typegen!("point", r#"{ "x": 1, "y": 2 }"#);will create the typePointjson_typegen!("foo_bar", r#"{ "x": 1, "y": 2 }"#);will create the typeFooBarjson_typegen!("Points", r#"[{ "x": 1, "y": 2 }]"#);will create the typePoint, so you get aVec<Point>, but will not definePointsFor all cases where the requested type name is legal it should be possible to just reserve the name up front, and then add an alias. Just have to make sure to allow a named root type to use the requested type (e.g.
type Point = Point1; struct Point1 { ... }would be a bit silly`).