Open G-Rath opened 4 years ago
I've just found a similar typo in the RegExp
interface in es5.lib
:
The last part of the comment of the comment doesn't seem relevant:
The regExp argument is a Regular expression object. It can be a variable name or a literal.
My guess is that is the description for the regexp
param taken by #match
, which reads very similar:
I have found another comment issue in replace():
/**
* Replaces text in a string, using an object that supports replacement within a string.
* @param searchValue A object can search for and replace matches within a string.
* @param replaceValue A string containing the text to replace for every successful match of searchValue in this string.
*/
replace(searchValue: { [Symbol.replace](string: string, replaceValue: string): string; }, replaceValue: string): string;
This comment is misleading because this function replaces all occurrences when the pattern is a regular expression but only the first occurrence when it is a literal as explained in https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace :
The replace() method returns a new string with some or all matches of a pattern replaced by a replacement. The pattern can be a string or a RegExp, and the replacement can be a string or a function to be called for each match. If pattern is a string, only the first occurrence will be replaced.
which is confirmed by running the following code:
console.log("foo".replace("o", "O")); // => fOo
console.log("foo".replace(/o/g, "O")); // => fOO
TypeScript Version: 3.0.0-dev.201xxxxx
Search Terms: typos, string, lib, es2015.symbol.wellknown
I've wiped the majority of the template since this is a typo report. I was originally going to just make a PR but the template had:
The typo itself is that
String#match
inlib.es2015.symbol.wellknown
has it's param description pasted in the middle of it's method description:https://github.com/microsoft/TypeScript/blob/d2c5d54242c69effbed0ebb27033047e0c995589/src/lib/es2015.symbol.wellknown.d.ts#L209-L212
My PR replaced it with "with a regular expression" - Let me know what the correct way to proceed with this is π