Pass a image generator URL to u parameter

[lovato]

I am trying to fetch an image from GoogleMaps static api. I faced 2 problems: a) first, I had to replace '&' for '&' ... thats ok. b) I got 'key error' at this point:

(u'http://maps.googleapis.com/maps/api/staticmap?markers=color:red|-29.828736,-51', u'.150409&zoom=17&size=600x600')

It is spliting for '.', and getting the 2nd part as extension, which in this case produces an error. The used URL was:

http://imagebox.lovato.geek42.org/imgsizer/remote?w=300&u=http://maps.googleapis.com/maps/api/staticmap?markers=color:red%7C-29.828736,-51.150409%26zoom=17%26size=600x600

The error happens on line: hashlib.md5(remote_url).hexdigest() + os.path.splitext(remote_url)[1]

The solution I found was: http://imagebox.lovato.geek42.org/imgsizer/remote?w=300&u=http://maps.googleapis.com/maps/api/staticmap?markers=color:red%7C-29.828736,-51.150409%26zoom=17%26size=600x600%26ext=.jpg

By adding a ext fake parameter to my external URL, I succeeded.

[iurisilvio]

Flask-Images define the image type from the extension. It is easy to guess extension from mimetype. It is a valid use case and should work fine.

The problem with the & happens because of some urlencoding issue in URL building, which can be fixed in Flask-Images.

[mikeboers]

This just seems like bad path/URL parsing and URL generation to me. Let me see if I can nail these both down quickly...

[mikeboers]

I've fixed this, and pushed to the PyPI as v1.1.5.

Cheers,

Mike

[mikeboers]

I've actually reverted the 1.1.5 deployment; it will be ready very shortly.