default call

[majiq3233]

python 3.9, Windows 10

When clicking the left button on the icon, an error appears: TypeError: 'tuple' object is not callable

replace to fix: _base.py

old

    def __call__(self):
        if self._menu is not None:
            self._menu(self)
            self.update_menu()

new

    def __call__(self):
        if self._menu is not None:
            for idx, item in enumerate(self._menu):
                if item.default:
                    self._menu[idx](self)
                    continue
            self.update_menu()

[moses-palmer]

Thank you for your report.

How did you create the menu? Please note that, as noted in the documentation, the menu argument passed to the constructor must be an instance of pystray.Menu. Using a tuple or a list will seemingly work, but crash for the default menu action.

[majiq3233]

tried two mini variants:

        pystray.Icon('name', image, menu=(
                item('Show', self.show_window, default=True),
                item('Quit', self.close_app),
            )
        ).run()

        menu = (
            item('Show', self.show_window, default=True),
            item('Quit', self.close_app),
        )

        icon = pystray.Icon("name", image, "title", menu)
        icon.run()

this code actually works:

        image = Image.open("icon.ico")

        menu = pystray.Menu(
            item('Show', self.show_window, default=True),
            item('Quit', self.quit_window),
        )

        icon = pystray.Icon("name", image, "title", menu)
        icon.run()

menu = pystray.Menu(