msracver / Deformable-ConvNets

Deformable Convolutional Networks
MIT License
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dcn = DCN(64, 64, kernel_size=(3,3), stride=1, padding=1, deformable_groups=2).cuda() #265

Open xiaoliqiangxxqzz opened 5 years ago

xiaoliqiangxxqzz commented 5 years ago

why deformable_groups is 2? And what means deformable_groups?