Open HeikoOnnebrink opened 7 years ago
here the fix ...
// WaitFor polls a predicate function, once per second, up to a timeout limit. // It usually does this to wait for a resource to transition to a certain state. // Resource packages will wrap this in a more convenient function that's // specific to a certain resource, but it can also be useful on its own. func WaitFor(timeout int, predicate func() (bool, error)) error { start := time.Now() for { // Force a 1s sleep time.Sleep(1 * time.Second)
// If a timeout is set, and that's been exceeded, shut it down
if timeout >= 0 && time.Since(start) >= time.Duration(timeout) * time.Millisecond {
return errors.New("A timeout occurred")
}
// Execute the function
satisfied, err := predicate()
if err != nil {
return err
}
if satisfied {
return nil
}
}
}
timeout in Seconds > if timeout >= 0 && time.Since(start) >= time.Duration(timeout) * time.Second {
I am also facing the same issue while using this utility function. Would like to know when would this case be handled ? Is it planned for any new release ?
I had issues that servers.WaitForStatus does not timeout when I pass timeouts > 60 seconds I debugged and found that at the end the timeout is implemented in gophercloud package func WaitFor. As it looks like the code has bug as var start is of type int and can have a range 1..60 If I pass timeout > 60 it will never terminate, if I pass values <= 60 wait time is random
Go lang spec: func (t Time) Second() int Second returns the second offset within the minute specified by t, in the range [0, 59].
package gophercloud
func WaitFor(timeout int, predicate func() (bool, error)) error { start := time.Now().Second() for { // Force a 1s sleep time.Sleep(1 * time.Second) // If a timeout is set, and that's been exceeded, shut it down if timeout >= 0 && time.Now().Second()-start >= timeout { return errors.New("A timeout occurred") } // Execute the function satisfied, err := predicate() if err != nil { return err } if satisfied { return nil } } }