Open rspeer opened 13 years ago
Ideally, Forge will prune its decisions so it doesn't have to consider all 2^n possibilities. Lots of the possibilities will be equivalent except for $0 cards, or will be pointless because they bring the total over $8 or $11.
Ideally, Forge will prune its decisions so it doesn't have to consider all 2^n possibilities. Lots of the possibilities will be equivalent except for $0 cards, or will be pointless because they bring the total over $8 or $11.