How to get a call to server and receive the result in one line?

slazarov / python-signalr-client

SignalR client for python based on asyncio.

MIT License

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Open nkfeiyang opened 5 years ago

nkfeiyang commented 5 years ago

I just want to invoke an event on server and then receive some message, like the local method call.

e.g.

msg = hub.server.invoke('SubscribeToExchangeDeltas', 'BTC-ETH')

Thanks,