Open matiasmorant opened 5 years ago
a && b ? c : d compiles to a && (b ? c : d). Same problem for || operator
a && b ? c : d
a && (b ? c : d)
||
I can't seem to replicate this. Does it compile incorrectly here: https://www.sweetjs.org/browser/editor.html ?
a && b ? c : d
compiles toa && (b ? c : d)
. Same problem for||
operator