Closed ilyasarafath closed 3 months ago
This kind of try catch will never work due to how this code and Flutter fundamentally works. So unfortunately I can't do anything
Is it possible return "true" or "false" from this function "showAndUploadToSentry" based on the result?
For any customization beyond the default API you have to go custom. Then you can catch exceptions, know the result and so on.
Version
3.0.0
Library
feedback_sentry
Flutter channel
stable
Flutter version
3.19.2
Platform
Android, iOS
Details
Am using feedbacksentry package to capture user feed and send to Sentry, The internal exception is not caught in the catch block ` try { BetterFeedback.of(context).showAndUploadToSentry( name: "Test", email: AppConstants.supportMail, ); } catch () { //exception not catching here }`
Steps to reproduce
Output of
flutter doctor -v