Closed FlorianRudolf closed 10 years ago
segment_t is something like a segment handle not the actual segment. So:
segment_t my0 = segmentation.make_segment(); segment_t my1 = my0;
my0 and my1 are essentially the same segment. Is this behaviour ok?
Solution: segment_t -> segment_handle_t
ee28bb3ac8530010d57f105a448609b086421a8c done
segment_t is something like a segment handle not the actual segment. So:
segment_t my0 = segmentation.make_segment();
segment_t my1 = my0;
my0 and my1 are essentially the same segment. Is this behaviour ok?