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weinbergerlab / InterventionEvaluatR

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unable to specify 'variants' #77

Closed DanWeinberger closed 3 years ago

DanWeinberger commented 3 years ago

Likely from: lapply( analysis$.private$variants[c('time', 'time_no_offset', 'pca', 'full')], function(variant) variant$name ) )

DanWeinberger commented 3 years ago

could replace with

lapply( analysis$.private$variants[variants], function(variant) variant$name ) )

DanWeinberger commented 3 years ago

Resolved in commit 6ca1c01ac62e86c47af146b1a3abbd2c7baf44b9