Conditional include based on environment variables [Feature Req]

[shadow1runner]

Because I'm in the dilemma right now I'm wondering if other users might have the same use case as I do:

I need to do include code files conditionally (due to different build targets with different instruction set), therefore it would be nice if I could define an environment variable which is passed via e.g. include( { buildVersion: 1.0}) and I can require or include the files based on a condition.

Or does somebody of you guys have a convenient solution for this? Currently I'm looking at gulp-regex-replace to do this job

Thanks

[wiledal]

I feel this is a bit of an edge case which could be solved in how you set up your build scripts. In this case I would probably target different files, so that you can control the includes.

main-vXX.js or similar for the different build targets... Possibly you can use yargs or similar to add some more modularity to your gulp script.

var gulp = require("gulp"),
    watch = require("gulp-watch"),
    include = require("gulp-include"),
    argv = require("yargs").argv;

gulp.task("build", function() {
  if (!argv.version) return console.log("No version set, please use --version");

  gulp.src("assets-src/js/main-v"+argv.version+".js")
    .pipe(include())
    .pipe(gulp.dest("assets/js"));
});

You'd then call gulp build --version 1.0 which will build assets-src/js/main-v1.0.js.

[shadow1runner]

I agree that that's really an edge case and thus shouldn't be part of gulp-include. But the feature I was originally thinking of was more some kind of preprocessor (#ifndef etc.) - but yeah, this is more compiler-related than anything else.