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springboot 2.2.0.M5 invalid
jasypt:
encryptor:
private-key-format: pem
private-key-location: secret/private.pem
Error starting ApplicationContext. To display the conditions report r…
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The main README suggests inserting property entries like this:
```
jasypt.encryptor.password=${JASYPT_ENCRYPTOR_PASSWORD:}
```
However, Spring Boot's property binding already handles this inte…
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For some strange reason I get this error on our DEV servers. However, when we run the same application on our local machines it works fine.
I get the same problem as this one: [https://stackoverflo…
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Hi,
I have jasypt-spring-boot-starter in my dependencies.
I have the --jasypt.encryptor.password as a program argument.
I am also using the StandardEncryptableEnvironment:
```
new SpringApplica…
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When I'm trying to inject default StringEncryptor instance, it works only for versions prior 2.*.
Here is the dependency/code:
```
com.github.ulisesbocchio
jasypt-spring-boot-s…
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Hi, when my app resolves encrypted property those properties are showing funny characters and I'm no able to provide the right credentials
My property is = �U�|�a װ�ı����QY��F0ldo
compile'com.…
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Hi, Can jasypt-spring-boot support some AES algorithm ？how can I set jasypt.encryptor.algorithm?
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Is there any advice on how to encrypt a string from the CLI?
I assumed that i could just use the same Class that jasypt's bin/encrypt.sh uses, but that yields garbage when decrypted inside a Spring…
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Greetings.
I did a test with both versions and using the same spring boot project and jaspypt-spring boot version 2.1.1. I used PBEWITHSHA1ANDRC2_40 algorithm it's one of them that works in both ja…
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Referring to #88 thanks for pointing out the configuration for `algorithm=PBEWITHHMACSHA512ANDAES_256`.
But anyhow, I could not get it to run. I am generating my password by passing the parameters `a…