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例如R18 R18G的分类,可以通过掩码实现吗?多谢
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Q:为什么跳过4.0?
A:4.0计划其实之前在3.0的时候已经有了,但是因为P站改版导致化为泡影,于是直接跳到新的计划。
Q:什么时候能出来?
A:以三次元工作为优先,毕竟要养家。目前三次元有比较重要的事情排在前面。
Q:5.0版原理,能用多久?
A:1~3版都是解析的桌面版网页,通过研究阅读,准备采用[PixivPy](https://github.com/upbit/pix…
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## Meta -
- OS:
>Window 10
- Selenium Version:
>
org.seleniumhq.selenium
selenium-java
2.44.0
- Browser:
> Chrome webDriver.
- Browser Version:
>Chrome 63.0.3239.1…
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`[�������寞湺] http://i3.pixiv.net/c/480x960/img-master/img/2016/04/30/08/42/32/56583142_p0_master1200.jpg
[ă��5/3čś�厜ĺŽ�ă��ă�Ťă�Šä¸�ć�°ĺ��ă�ľă�łă��ă�Ť] http://i1.pixiv.net/c/480x9…
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Is this possible at all? All I'm getting is limit_r18_360.png and I can't seem to figure out how to auth and circumvent R-18 block, if that is even possible.
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Just want to ask if there is any API to get the illustrations details (e.g. title, caption, urls) for given illust_id without go through the user_id illustrations?
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I get the following error when I try a random artist from the front page. I assume maybe the recent front-end changes have broken something?
Member Url: http://www.pixiv.net/member_illust.php?id=6996…
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API me_feeds() response was changed while Pixiv release iOS 6.x API (app-api), it [broken the CI](https://travis-ci.org/upbit/pixivpy/jobs/143927194):
``` py
json_result = api.me_feeds(show_r18=0…
upbit updated
8 years ago
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我在做网页版下载脚本,以前以为多图只能下载zip,但是用了您研究的api发现可以下载到有透明的原图了,但目前发现多图只在metadata里能获取到帧数,而/users/{UID}/works.json返回的metadata是null,只有/works/{illust_id}.json才返回metadata。
我注意到/users/{UID}/works.json附加include_stats=t…
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http://spapi.pixiv.net/iphone/member_illust.php 这个地址提示 404