-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…
-
```
What steps will reproduce the problem?
1.By using query "SELECT ID , COUNT(ID) FROM sandbox.test GROUP BY UID ORDER BY
UID"
2.Execute query.
What is the expected output? What do you see instead?…