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Add the ability to create menus.
Zakay updated
12 years ago
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```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
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```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
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```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
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Currently, if you instantiate a CCMenu without any children and add it to another node, the code flips out during some operations (ex. itemForTouch) because its list of children is null.
Maybe add so…
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```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
-
```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
-
```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
-
```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…
-
```
What steps will reproduce the problem?
1. 一个有3个CCMenuItemLabel的menu
2. 按住的一个item,手指不动
What is the expected output? What do you see instead?
ccTouchesMoved 函数中, CCMenuItem currentItem = itemForTou…