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When I capture a group using rsub, I'm unable to access the capture using $1 or \1. For example
@rsub s/(test)/$1/
prints $1
Am I missing something?
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In Heptapod by @dgrisby on Jun 14, 2023, 10:17
This is a minor issue, but I have some code that refers to `datetime.datetime.__rsub__`, which is present in CPython 3.9, but not in PyPy 7.3.11:
```
$…
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```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …
-
```
What steps will reproduce the problem?
1. in the python interpreter do
2. import euclid
3. a = euclid.Vector2(1,1)
4. (0,0) - a
What is the expected output? What do you see instead?
(-1.0, -1.0) …