Figure 14.1.2 does not match Example 14.1.1

[0-andy-0]

Somehow the sine is multiplied by -1 in the asy files.

In the text 14_Line_Integral_Intro.tex you have:

134: {Find the area under the surface $f(x,y) =\cos(x)+\sin(y)+2$ over the curve $C$, which is the segment of the line $y=2x+1$ on $-1\leq x\leq 1$, as shown in Figure \ref{fig:linescalarfield2}.

138: We find the values of $f$ over $C$ as $f(x,y) = f(t,2t+1) = \cos(t)+\sin(2t+1) + 2$.

while in the figures figlinescalarfield2_3D.asy and figlinescalarfield2b_3D.asy you have

4:// The surface is z=cos(x)+sin(y)+2; the path is the line 38://Draw the surface z=cos(x)+sin(y)=2 40:return (t.x,t.y,-sin(t.y)+cos(t.x)+2); 48:triple g(real t) {return (t,2*t+1,-sin(2t+1)+cos(t)+2);}

and

4: // The surface is z=cos(x)+sin(y)=2; the path is the line 37://Draw the surface z=cos(x)+sin(y)=2 39:return (t.x,2*t.x+1,t.y*(-sin(t.x*2+1)+cos(t.x)+2)); 47:triple g(real t) {return (t,2*t+1,-sin(2t+1)+cos(t)+2);}

[APEXCalculus]

Nice catch. I'll work on fixing this. Thanks.

[0-andy-0]

Similarly in APEXCalculusPTX !

[APEXCalculus]

Yes. That's where the change will actually appear. Thanks.

[Gomesz785]

Is this issue solved?