Closed GoogleCodeExporter closed 9 years ago
We now unparse exit() as exit() instead of exit(0), but we still unparse exit;
(without brackets) as exit() (with brackets, but without an argument).
Original comment by edskodev...@gmail.com
on 11 Nov 2007 at 10:45
Original comment by edskodev...@gmail.com
on 11 Nov 2007 at 6:15
Original issue reported on code.google.com by
edskodev...@gmail.com
on 10 Nov 2007 at 5:20