Extension syntax error

[ThomasKFitzgerald]

Terminal window:

PS C:\DevOps\Python\Learning\Databases> sqlite3 SQLite version 3.46.1 2024-08-13 09:16:08 (UTF-16 console I/O) Enter ".help" for usage hints. Connected to a transient in-memory database. Use ".open FILENAME" to reopen on a persistent database. sqlite> .open test.db sqlite> CREATE TABLE investments (coin_id TEXT, currency TEXT, anount REAL); sqlite> .tables investments sqlite> .headers on sqlite> .mode column sqlite> pragma table_info('investments'); cid name type notnull dflt_value pk

---

0 coin_id TEXT 0 0 1 currency TEXT 0 0 2 anount REAL 0 0 sqlite> INSERT INTO investments VALUES ('bitcoin', 1.0, 'usd'); sqlite> SELECT * FROM investments; coin_id currency anount

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bitcoin 1.0 usd sqlite> .exit PS C:\DevOps\Python\Learning\Databases>

This is a new DB.

When clicking open database this is the error:
" [9:58:20 AM][vscode-sqlite][INFO] Activating extension vscode-sqlite v0.14.1... [9:58:20 AM][vscode-sqlite][INFO] Extension activated. [10:03:05 AM][vscode-sqlite][ERROR] Failed to open database 'c:\DevOps\Python\Learning\Databases\test.db': Parse error near line 4: no such column: "table" - should this be a string literal in single-quotes? aster WHERE (type="table" OR type="view")
error here ---^ "

[Chisrra]

I have the same issue

[surbina85]

Currently having the same issue, I'm on Mac (Silicon) and can't open any .sqlite file despite being able to open them in other apps or extensions. I get the exact error about parson in line 4

[yayformojo]

Same issue - VSCode version is: Version: 1.93.1 Commit: 38c31bc77e0dd6ae88a4e9cc93428cc27a56ba40 Date: 2024-09-11T17:20:05.685Z Browser: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Code/1.93.1 Chrome/124.0.6367.243 Electron/30.4.0 Safari/537.36

[readandwrite864]

same here

possible duplicate of this