Open parthrparekh93 opened 7 years ago
Same happens in my case :/ How can I check wether advertiser is null without checking for bluetooth while initializing?
You can call:
If (BeaconTransmitter.checkTransmissionSupported(context)) == BeaconTransmitter.SUPPORTED) { BeaconTransmitter = new BeaconTransmitter(context); }
If Bluetooth is off the check will return NOT_SUPPORTED_CANNOT_GET_ADVERTISER
On Thu, Aug 20, 2020 at 4:22 AM St3ffB3 notifications@github.com wrote:
Same happens in my case :/
How can I check wether advertiser is null without checking for bluetooth while initializing?
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When I initialize BeaconTransmitter with Bluetooth OFF, I am unable to start advertising which is correct. However, when I switch Bluetooth ON later, it still throws NullPointerException. I realized that this is because BeaconTranmsitter has BluetoothLeAdvertiser as an instance variable and it is null because it was initialized when Bluetooth was OFF.
Expected behavior
When I switch my Bluetooth ON later, it should change the BluetoothLeAdvertiser instance so that advertising can begin
Actual behavior
When I switch my Bluetooth ON later, BluetoothLeAdvertiser instance is null and cannot start advertising. This is what I think. If there is a workaround or a good reason to keep it as it is, let me know too :)
Steps to reproduce this behavior
Initialize BeaconTransmitter when Bluettooth is OFF. Start advertising. It will throw exceptions. Switch Bluetooth ON. It will still throw exception
Cannot start advertising due to exception java.lang.NullPointerException: Attempt to invoke virtual method 'void android.bluetooth.le.BluetoothLeAdvertiser.startAdvertising(android.bluetooth.le.AdvertiseSettings, android.bluetooth.le.AdvertiseData, android.bluetooth.le.AdvertiseCallback)' on a null object reference
Mobile device model and OS version
Android Beacon Library version
2.11 IMPORTANT: This forum is reserved for feature requests or reproducible bugs with the library itself. If you need help with using the library with your project, please open a new question on StackOverflow.com.