apollo 感知模块 8个统计量中的distance_data

[wdxpython]

[lianglia-apollo]

Could you rephrase your question in English? Some of our perception team members are not native Chinese speakers.

[wdxpython]

Yes，I am not very good at English.Questions are as follows： When calculating the distance between the center of the cell and the origin in the eight channel features --distance_data, distance_data[idx] = static_cast(std::hypot(center_x, center_y) / 60.0 - 0.5); How do you understand it, can you explain it? The range is [-0.5, 0.91], is this normalized? The projection to the 2D grid has been calculated previously. Why not go to the lidar coordinate system without projecting to the 2D grid?

[wdxpython]

Could you rephrase your question in English? Some of our perception team members are not native Chinese speakers.

Yes，I am not very good at English.Questions are as follows： When calculating the distance between the center of the cell and the origin in the eight channel features --distance_data, distance_data[idx] = static_cast(std::hypot(center_x, center_y) / 60.0 - 0.5); How do you understand it, can you explain it? The range is [-0.5, 0.91], is this normalized? The projection to the 2D grid has been calculated previously. Why not go to the lidar coordinate system without projecting to the 2D grid?

[techoe]

Could you elaborate which code or document you are referring?

[natashadsouza]

@wdxpython which document were you referring to? Were you able to find the answer to your question?