Closed ApolloFortyNine closed 8 years ago
Or maybe use many and statements, like ((beatmap_id == x[0].beatmap_id & enabled_mods == x[0].enabled_mods) & (beatmap_id == x[1].beatmap_id & enabled_mods == x[1].enabled_mods))
Though it may return too many at one time, using too much memory. yield_per might be useful here.
Same as #81
SELECT DISTINCT beatmap_id FROM beatmaps b WHERE b.beatmap_id NOT IN (SELECT beatmap_id FROM beatmap_info)
There may be a way, similar to the above, to write one query that does the work of all 50.