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AppImageCrafters / appimage-builder

GNU/Linux packaging solution using the AppImage format
MIT License
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Can't select my binary during recipe generation #332

Open Fabxx opened 11 months ago

Fabxx commented 11 months ago

I converted a bash script into a binary executable with shc, the file output provides these details:

ELF 64-bit LSB pie executable, x86-64, version 1 (SYSV), dynamically linked, interpreter lib64/ld-linux-x86-64.so.2, BuildID[sha1]=d38ee10cecd4336c489f562995c9b9e24743680d, for GNU/Linux 3.2.0, stripped

Then i run the generate command and i'm asked to choose the path of the binary, which is in AppDir/usr/bin/ but the script only allows me to choose the default binary provided by qt-appimage-template/

./appbuilder.AppImage --generate
INFO:Generator:Searching AppDir
? ID [Eg: com.example.app]: myscript
? Application Name: script
? Icon: QtQuickControls2Application
? Executable path: (Use arrow keys)
 » usr/bin/qt-appimage-template

I don't know what's causing this but i can't add another path to select my executable instead.