In this example
var s = "www.google.com".toSlice();var delim = ".".toSlice();var parts = new string[](s.count(delim) + 1);
parts should contain three elements www / google / com but there are only two dots in www.google.com string.
(count + 1) is required instead of (count) if we want all three parts of the string to be in parts array.
Arachnid
commented
7 years ago
In this example
var s = "www.google.com".toSlice();var delim = ".".toSlice();var parts = new string[](s.count(delim) + 1);parts should contain three elements
www/google/combut there are only two dots inwww.google.comstring. (count + 1) is required instead of (count) if we want all three parts of the string to be inpartsarray.