C++ Solution

[Ivan2001otp]

APPROACH

1. I have used two Pointer approach to solve this problem.
2. Initially the first pointer will point to second element of vector, and traverses till last second element of vector.
3. I will create a pointer immediate previous to the first pointer , now I will check whether the elements of previous pointer and current-pointer are different & element pointed by current pointer and immediate next element is different .
4. If this condition satisfies then , I will add the element into the variable and return boolean value specifying that the unique element exists or not.
5. Further I have added two conditions to handle , what if first element or last element of vector is unique.
6. In any case , if the unique Element does not exist then I have printed the verdict in console.

OUTPUT

• Driver Program

• Util Function

• Input & output results

[Ivan2001otp]

APPROACH

1. I have used two Pointer approach to solve this problem.
2. Initially the first pointer will point to second element of vector, and traverses till last second element of vector.
3. I will create a pointer immediate previous to the first pointer , now I will check whether the elements of previous pointer and current-pointer are different & element pointed by current pointer and immediate next element is different .
4. If this condition satisfies then , I will add the element into the variable and return boolean value specifying that the unique element exists or not.
5. Further I have added two conditions to handle , what if first element or last element of vector is unique.
6. In any case , if the unique Element does not exist then I have printed the verdict in console.

OUTPUT

• Driver Program

• Util Function

• Input & output results