Closed dv0 closed 5 years ago
For example:pop dword ptr [esp+4]. In this instruction execution is divided into three steps: temp <= [esp] esp <= esp + 4 [esp + 4] <= temp so,in fact the destination address is “[esp+8]”.
ok ok, that's right. let's see how can we solve this specific case.
Has this been fixed yet?
For example:pop dword ptr [esp+4]. In this instruction execution is divided into three steps: temp <= [esp] esp <= esp + 4 [esp + 4] <= temp so,in fact the destination address is “[esp+8]”.