Possibility to define default value of procedure or macro argument.
There is possible conflict with procedure assignment.
inc:macro x:byte by:byte=1 =
x = x + by
In this case, we would need to use ().
inc:macro(x:byte by:byte=1) =
x = x + by
Original issue reported on code.google.com by rudla.ku...@gmail.com on 20 Jan 2011 at 2:02
Original issue reported on code.google.com by
rudla.ku...@gmail.com
on 20 Jan 2011 at 2:02