Feature: show if currently connected

[GoogleCodeExporter]

What steps will reproduce the problem?
1. Starting officeManager
2. It is impossible to know if it started up correctly without issuing an 
execute() and trying if an exception will be thrown.

What is the expected output? What do you see instead?
I would like to have a function isRunning() to check if the openOfficeService 
is running and jodconverter is connected to it.

I've attached a patch for this. It is debatable if it should return true or 
false if ExternalOfficeManager is started with connectOnStart=false:
- False: It is not currently connected
- True: It is ready to receive tasks.

Original issue reported on code.google.com by benjamin...@uni-siegen.de on 16 Aug 2011 at 7:37

Attachments:

• isRunning_rev205.patch

[GoogleCodeExporter]

Is there anything I can do to increase the chances of inclusion of this patch? 
Write some unit tests maybe?

Original comment by benjamin...@uni-siegen.de on 5 Sep 2011 at 6:58

[GoogleCodeExporter]

The code looks fine to me. I don't see any reason not to include it. Still, 
Mirko has the final say.
Can I ask why you want this feature? 

Original comment by shervin.asgari@gmail.com on 12 Sep 2011 at 12:31

[GoogleCodeExporter]

There are two reasons:

1) It is considered bad practise to branch according to wether an exception 
will be thrown or not. However, currently, this was the only way to detect if 
connect() worked: by testing if the convert() throws an exception.

2) The library that I am currently building 
(https://github.com/benjamin4ruby/java-thumbnailer) tries to fail as early as 
possible, thus even before  the first convert() takes place.

Original comment by benjamin...@uni-siegen.de on 15 Sep 2011 at 7:52

[GoogleCodeExporter]

Fixed in trunk.
If Mirko objects, he can just revert the code

Original comment by shervin.asgari@gmail.com on 15 Sep 2011 at 8:07

• Changed state: Fixed
• Added labels: Type-NewFeature