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3D mesh generation: Replace operator()(K::Point_3 p) by something with many points? #3874

Open nschloe opened 5 years ago

nschloe commented 5 years ago

Functions like Mesh_domain::create_implicit_mesh_domain are called with domain objects that a have

K::FT
operator()(K::Point_3 p) const
{
  // return the distance to the boundary
}

This is an evaluation returning the signed distance of a point p to the domain boundary. For mesh generation, this operator is then called with point after point.

For many, if not all of my domains, I could compute the distance much faster if I wasn't forced to do it one after the other, but with many points at once. (Using higher-level BLAS routines, for example.)

Is it possible to make the the mesh generation ask for many points at once?

MaelRL commented 5 years ago

The algorithm works by iteratively inserting points whose position is chosen to best "break" a given element into smaller elements. That position is usually the circumcenter of the Delaunay ball. Thus, this new position is unfortunately dependent on the positions at the step 'n-1'.

However, there could be (at least) two ways to not compute all positions one by one:

@lrineau and @janetournois might have better ideas.

nschloe commented 5 years ago

computed by shooting random rays

Since the rays are all independent, they could be computed at the same time.

it is likely that all simplices of the mesh must be refined,

Yes, I assumed that there are operations which take place for all cells individually.

Unfortunately, that would be quite a few very low level changes...

I suppose. In the end, it should come down to looking for loops like

for (auto cell in cells) {
   // evaluate domain.operator()(...)
}
nschloe commented 4 years ago

This came back to bite me again.

For me to understand, do you build the mesh as follows? Build a basic mesh and then refine iteratively, i.e.,

Do you optimize after each step? Where are the most operator() calls spent?

janetournois commented 4 years ago

For me to understand, do you build the mesh as follows? Build a basic mesh and then refine iteratively, i.e.,

* picking a bad cell,

* inserting a node at the circumcenter (or some other point) of the cell,

the new node does not have to be in the cell, but in its Delaunay ball, to make sure the cell disappears from the mesh

* call `domain.operator()` to keep the new point inside,

This kind of operator is called on newly created cells to keep the "restricted Delaunay triangulation" valid

* doing some other operations to keep the mesh conforming,

the point is inserted in the regular triangulation while keeping it valid, and the "domain status" is updated above. There are no extra-operations here

* and repeat.

Do you optimize after each step? Where are the most operator() calls spent?

Optimization is used only after the end of mesh refinement.

The operator() you mention (I guess you mean the one that updates the cells status wrt the restricted Delaunay triangulation) is called a lot during optimization, because each cell is updated after each move. In global optimizers though, it is possible to compute all moves, apply them all, and then update the full restricted Delaunay triangulation at a time.

nschloe commented 4 years ago

Thanks @janetournois for the reply.

The operator() you mention

This is the operator that, evaluated at a geometrical point x, returns the signed distance to the domain boundary. Did you understand it this way?

janetournois commented 4 years ago

Yes, it is part of what we call the "oracle".

nschloe commented 4 years ago

The operator() you mention (I guess you mean the one that updates the cells status wrt the restricted Delaunay triangulation) is called a lot during optimization, because each cell is updated after each move.

Okay great. If all cells are updated after each step, then at least the algorithm would allow for calling operator() with many points at once, right?

janetournois commented 4 years ago

Theoretically yes, but IIRC the code does :

for each vertex v
  compute_move(v)
  apply_move(v)
  call oracle on all impacted cells (about 30)

To call oracle on more cells at once, it would require changing the code for

for each vertex v
   compute_move(v)
for each vertex v
   apply_move(v)
call oracle on all cells
nschloe commented 4 years ago

The oracle is called on geometric points x, so perhaps it really goes like

for each vertex v
  compute_move(v)
  apply_move(v)
  for adjacent_cell in adjacent_cells(v):  #  (about 30)
      call oracle on point in adjacent_cell

I would already help to

for each vertex v
  compute_move(v)
  apply_move(v)
  call oracle on points in all adjacent_cells at once (about 30)

Better of course:

for each vertex v
  compute_move(v)
  apply_move(v)

call oracle on all cells
janetournois commented 4 years ago

The oracle is called on geometric points x, so perhaps it really goes like

Note the oracle is called on the circumcenter of each cell

for each vertex v
  compute_move(v)
  apply_move(v)
  for adjacent_cell in adjacent_cells(v):  #  (about 30)
      call oracle on point in adjacent_cell

it's not only adjacent cells to v but all cells impacted by the move (remove(v) + insert(new_p)), namely the union of :

  • the cells created by remove(v) (filling the cavity left instead of incident_cells(v))
  • the cells created by insert(new_p), i.e. incident_cells(new_v) (both zones usually overlap, but they may not)

I would already help to

for each vertex v
  compute_move(v)
  apply_move(v)
  call oracle on points in all adjacent_cells at once (about 30)

Absolutely