Closed GoogleCodeExporter closed 9 years ago
Use:
JSONObject jo = (JSONObject)JSONValue.parse(ArrayString);
See "https://code.google.com/p/json-simple/wiki/DecodingExamples" for more
details.
Original comment by fangyid...@gmail.com
on 15 Jul 2014 at 3:08
Original issue reported on code.google.com by
Tyler.sa...@gmail.com
on 9 Jul 2014 at 4:20