CNES / RadiativeTransferCode-OSOAA

Ocean Successive Orders with Atmosphere - Advanced (OSOAA) : Accurate computation of the radiative tranfer into the Ocean-Atmosphere system including polarisation, coupling terms, and the agitated surface.
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The Junge's law model in OSOAA #19

Closed yichen-li2016 closed 7 months ago

yichen-li2016 commented 7 months ago

Hi,

Recently, while using OSOAA, I'm confused in two ways. First, I found that the Junge model in the Hydrosol models is N(D)=r-v, and in the open ocean, when v=4, I get the following particle size distribution. This result differs by many orders of magnitude from that in Stramski et al. 2001. So I would like to ask if there exists a coefficient K for the Junge distribution N(r) = Kr-v here, or is the unit of N(r) used by default in OSOAA [um**-4]? PSD image

Second, I see from the ANGLES.Log file that the number of Gauss angles used for phase function calculations is 40, distributed over [0, pi/2]. However, the number of angles in the HYD_MIE.Log file that I got is 83, distributed over [0, pi]. I would like to know how this is done in the actual calculation? Also, if I choose HYD.Model=2 and I set the same number of angles and distribution as in ANGLES.Log, can I get the same result as HYD_MIE.Log?

Best regards, Qiang

blafranc commented 7 months ago

Hello,

Response to question 1 : "Junge model" The size distribution is used to calculate the scattering and extinction cross-sections equivalent to an average particle size. The number of particles is not necessary to get these radiative terms. That is why the Junge distribution is expressed by N(r) = r-v and not by Kr-v.

Response to question 2 : "Gauss angles" N Gauss angles are calculated over [0, pi/2]. The opposite value of each Gauss angle is added to discribe the phase functions over [0, pi], giving to 2N angles. The angles 0°, 90° and 180° complete the list of angles for the log file, giving to 2N+3 angles.

Hoping these answers help. Best regards

yichen-li2016 commented 7 months ago

Hi,

Thank you, your reply has been of great help to me!

Best regards, Qiang