wslsq
commented
4 weeks ago main.js
const EmbeddedQueue = require("embedded-queue");
const sleep = require('util').promisify(setTimeout);
// global.PRINT_RUNNER
// global.PRINT_RUNNER_DONE
global.PRINT_QUEUE = null;
// 队列
EmbeddedQueue.Queue.createQueue({ inMemoryOnly: true }).then((queue)=>{
queue.process(
"print",
async (job) => {
data = job.data;
data.taskId = job.id;
// 0为失败，1为开始，99为成功(可以在具体执行中设置进度)
for (let i =0; i<=10000; i++){
job = await PRINT_QUEUE.findJob(job.id);
if (i == 0){
job.setProgress(1, 100);
PRINT_WINDOW.webContents.send("print-new", job.data);
MAIN_WINDOW.webContents.send("printTask", true);
}
console.log('jobProgress=====>'+job.progress)
if (job.progress == 99 || job.progress == 0){
PRINT_QUEUE.listJobs('INACTIVE').then((waitJobs)=>{
MAIN_WINDOW.webContents.send("printTask", waitJobs.length > 0);
});
break;
}
await sleep(6000); // 根据实际优化
}
},
1 //并发固定1
);
// handle job complete event
queue.on(
EmbeddedQueue.Event.Complete,
(job, result) => {
console.log("Job Completed.");
console.log(` job.id: ${job.id}`);
console.log(` job.type: ${job.type}`);
console.log(` job.data: ${JSON.stringify(job.data)}`);
console.log(` result: ${result}`);
}
);
global.PRINT_QUEUE = queue;
});utils.js
client.on("news", (data) => {
if (data) {
console.log('收到news');
data.socketId = client.id;
data.clientType = "transit";
// 注意删掉了taskId
PRINT_QUEUE.createJob({
type: "print",
data: { ...data },
}).then((job)=>{ });
}
});print.js
printXX(data).then(()=>{
PRINT_QUEUE.findJob(data.taskId).then((job)=>{
job.setProgress(99, 100)
});
}).catch((err) => {
PRINT_QUEUE.findJob(data.taskId).then((job)=>{
job.setProgress(0, 100)
});
})
.finally(() => {
//原操作删除
});
printXX = (data)=>{
return new Promise((resolve, reject) => {
// 转码成功
PRINT_QUEUE.findJob(data.taskId).then((job)=>{
job.setProgress(50, 100)
});
// 下载成功
PRINT_QUEUE.findJob(data.taskId).then((job)=>{
job.setProgress(60, 100)
});
// 发送打印成功
PRINT_QUEUE.findJob(data.taskId).then((job)=>{
job.setProgress(70, 100)
});
})
} 
Xavier9896
现在用的队列concurrent-tasks是阻塞的， 假设一次打印用5秒，于10.00.00发了2个news：A和B，日志如下， [10.00.00]收到A [10.00.00]执行A [10.00.05]收到B [10.00.05]执行B
理想状态下 [10.00.00]收到A [10.00.00]收到B [10.00.00]执行A [10.00.05]执行B
这样如果需要在收到任务做相关操作，会非常不方便。 一般插入任务不影响，另外起一个单并发消费任务会好一点。 如这个库 https://github.com/hajipy/embedded-queue
谢谢