Open Clear2 opened 4 years ago
func main() {
node1 := new(ListNode)
node1.Value = 1
node2 := new(ListNode)
node2.Value = 2
node3 := new(ListNode)
node3.Value = 4
node1.Next = node2
node2.Next = node3
node4 := new(ListNode)
node4.Value = 1
node5 := new(ListNode)
node5.Value = 3
node6 := new(ListNode)
node6.Value = 4
node4.Next = node5
node5.Next = node6
node7 := mergeTwoLists(node1, node4)
PrintNode(node7)
}
因为原始两个链表都是有序的! 所以题目就很简单了