[jellyfin] Parse info from ItemName

[Coloradohusky]

Grab album title and track title from ItemName (artist title is already parsed)

album title:
For example, if we have the string "(e)y(e)s w/o a %brain% (Eternal Home)" it should return "Eternal Home"
Or if we have "Mr. Self Destruct (The Downward Spiral (deluxe edition))" it should return "The Downward Spiral (deluxe edition)"

I'm trying to locate the parenthesis which matches the ending parenthesis in a string.
The parenthesis we want to match will always be the last character in the string, and it will always have a matching parenthesis.
I've tried doing parenthesis matching with Regex, but it gets confused by extra parenthesis (such as (deluxe edition) or (e)y(e)s)
Will look something like def return_within_parenthesis(string): return stuff_within_parenthesis
The strings will not always have balanced parenthesis
I've tried regex but can't figure out how to get it to match the correct parenthesis
Ie, "\(.+\)$" fails on the first example (the Eternal Home example) but works on the Downward Spiral example

[Coloradohusky]

So we have four different ItemName schemes to work with:

No extra parenthesis

• The Girl Gets Around (Footloose: The Musical)
• grimace_smoking_weed.jpeg (God's Country)

  Album parenthesis

• Bring da Ruckus (Enter the Wu-Tang (36 Chambers))
• Something in the Way (Nevermind (super deluxe))

  Song parenthesis

• Her and I (Slow Jam 2) (I'm in Your Mind Fuzz)
• (e)y(e)s w/o a %brain% (Eternal Home)

  Both album and song parenthesis

• Burn (soundtrack version) (The Downward Spiral (deluxe edition))
• When You Gonna Wake Up? (live in Toronto) (The Bootleg Series, Vol. 13: Trouble No More 1979-1981 (deluxe edition))

NOTE: Don't rely on )), what if album is (this (that) this)

[Coloradohusky]

I'll have to test it more in the morning, but I believe that this works for all cases (except when there are unbalanced parenthesis in the album name)

for test in list_strings:
    song = test[::-1]
    parenthesis = 0
    for i in range(len(song)):
        if (song[i] != ")" and song[i] != "(") and parenthesis == 0:
            print(i)
            print(song[1:i-1][::-1])
            break
        else:
            if song[i] == ")":
                parenthesis = parenthesis + 1
            elif song[i] == "(":
                parenthesis = parenthesis - 1

I.e. The Girl Gets Around (Footloose: The Musical))) and The Girl Gets Around (((Footloose: The Musical) doesn't work, due to the unbalanced parenthesis, but The Girl Gets Around (Foo()tloose(): The Musical()()()()()) works