Open ian-bertolacci opened 4 years ago
No, not even close. For test 100x100x10 for 5 time steps on topology (1,1,1): bin/time: Maximum resident set size (kbytes): 73908 proc/status: VmPeak: 465160 kB amps: Maximum memory used on processor 0 : 102 MB
Those are all very different values.
for a test 100x100x10-5 (4,1,1): bin/time is useless, only gives one process: Maximum resident set size (kbytes): 56848 amps: Maximum memory used on processor 0 : 34 MB Maximum memory used on processor 1 : 35 MB Maximum memory used on processor 2 : 35 MB Maximum memory used on processor 3 : 34 MB total 138 (138000 KB)
proc/status VmPeak: 538340 kB VmPeak: 538844 kB VmPeak: 538608 kB VmPeak: 538404 kB 2154196 KB
I dont think this is a KiB vs KB thing, since any conversion from one to the other does not result in anywhere near the same storage values as the other systems.
compare bin/time memory value vs /proc/status. Are the different? By how much?