Closed DanielSank closed 2 years ago
I have
O(lambda) = exp(lambda A) B exp(-lambda A)
but actually the formalism works in the more general case where
O(lambda) = T(lambda)^dagger B T(lambda)
and T(lambda) obeys a schrodinger equation with "Hamiltonian" A.
I have
but actually the formalism works in the more general case where
and T(lambda) obeys a schrodinger equation with "Hamiltonian" A.