Closed mc0re closed 7 years ago
While ConvexHull.Create has an overload which accepts tolerance, Triangulation.CreateDelaunay does not. Would be nice to have that.
ConvexHull.Create
Triangulation.CreateDelaunay
This has now been added in version 1.0.17.0911. Thanks for pointing this out.
While
ConvexHull.Create
has an overload which accepts tolerance,Triangulation.CreateDelaunay
does not. Would be nice to have that.