Closed MaximMoinat closed 3 years ago
By replacing count(distinct source_value) by count(*), a nan value will also be counted. As the query already groups by source_value, the resulting count is the same.
count(distinct source_value)
count(*)
Fixed in the same push, thanks
By replacing
count(distinct source_value)
bycount(*)
, a nan value will also be counted. As the query already groups by source_value, the resulting count is the same.