Closed j-faria closed 6 years ago
Hi Joao,
Thanks for pointing that out. You're definitely right that it should read "0 for e >=1". But if I fix that, then I don't understand you comment about it not being defined for e = 0. p(e) does go to zero at e=0, but that's different than undefined. Or am I missing your point?
Thanks, Eric
On Wed, Sep 13, 2017 at 3:27 PM, João Faria notifications@github.com wrote:
I think there are a couple of typos in the eccentricity prior in model.pdf https://github.com/EPRV3EvidenceChallenge/Inputs/blob/master/model/model.pdf . As is, it's not defined for e=0. Also, "0 for e>=0" should read "0 for e >=1"
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Hey Eric, From what I understand, in order to truncate the distribution, you divide by the cdf (evaluated at e=1). But as is written, the denominator is 0 for e=0.
Hey Joao. That "e" in the cdf might be a typo. I'm pretty sure it should be e_max = 1, as you pointed out.
Oh, I see... Ben's right, of course... the normalizing constant is evaluated at e_max =1. I've updated the model.tex and model.pdf. Does that make everything more clear?
Sorry, I could've been a bit more clear in what was wrong. That was it, closing the issue.
I think there are a couple of typos in the eccentricity prior in model.pdf. As is, it's not defined for e=0. Also, "0 for e>=0" should read "0 for e >=1"